The radius of innermost orbit of a hydrogen atom is `5.3 xx 10^(-1)` m. What is the radius of orbit in the second excited state?

Explanation

The radius of the atom, whose principal quantur number in n, is given by
`r_(n) = n^(2)r_(0) = 5.3 xx 10^(-11) m`
where `r_(0)` =radius of innermost electron orbit for second excited state n=3
So `r_(3) =3^(2) xx r_(0) =9xx 5.3 xx 10^(-11)`
`implies r_(3) =4.77 xx 10^(-10)` m