On reaction with silver nitrate solution, the complex `CoCl_3 .4NH_3` gives precipitates corresponding to one/two chloride ions.

A coordination complex compound of cobalt has molecular formula containing five ammonia molecules, one nitro group and two chlorine atoms for one cobalt atom. One mole of this compound produces three mole ions in an aqueous solution. On reacting this solution with excess of silver nitrate solution, two moles of AgCl get precipitated. The formula of this compound would be

The complex [Co(NH_3)_5Br]SO_4 will give white precipitates with

When 0.01 mole of a cobalt complex is treated with excess silver nitrate solution, 4.305 g silver chloride is precipitated. The formula of the complex is

The solution of the complex [Cu(NH_3)_4]SO_4 in water will

The isomerism shown by the complex [CoCl_2(OH)_2(NH_3)_2] Br are

A coordination compound has the formula CoCl_3 .4NH_3 . It precipitates silver ions as AgCl and its molar conductance corresponds to a total of two ions. Deduce its structural formula and name the complex.

A coordination compound has the formula CoCl_3 .4NH_3 . It precipitates silver ions as AgCl and its molar conductance corresponds to a total of two ions. Replace ammonia molecules by two molecules of ethylenediamine and discuss isomerism in the resulting complex ion.

The questions given below consist of an Assertion and Reason. Assertion : The complex [Co(NH_3)_3Cl_3] does not give precipitate with silver nitrate solution. Reason : The given complex is non-ionizable.

True of False : CoCl_3 .3NH_3 complex is non-conducting.