A compound has been found to have magnetic moment of 3.9 B.M. How many unpaired electrons does it contain ?

How many unpaired electrons are present in Fe^+3 and Zn^+2 .

In [Fe(H_2O)_6]^(3+) , the magnetic moment corresponds to number of unpaired electrons equal to

If an element M has mass number 24 and atomic number 12, how many neutrons does its atom contain ?

[Cr(H_2O)_6] Cl_3 (At. no. of Cr = 24) has a magnetic moment of 3.83 B.M. The correct distribution of 3d electrons in the chromium of the complex is :

The magnetic moment of a transition metal ion is found to be 4.90 BM. The number of unpaired electrons present in the ion is

Consider the argon atom. For how many electrons does this atom have m_(l) = 1 ?

If hydrogen atoms (in the ground state ) are passed through an homogeneous magnetic field, the beam is split into two parts. This interaction with the magnetic field shows that the atoms must have magnetic moment. However, the moment cannot be due to the orbital angular momentum since l=0. Hence one must assume existence of intrinsic angular momentum, which as the experiment shows, has only two permitted orientations. Spin of the electron produce angular momentum equal to S=sqrt(s(s+1))(h)/(2pi) where S=+(1)/(2) . Total spin of an atom = +(n)/(2) " or "-(n)/(2) where n is the number of unpaired electrons. The substance which contain species with unpaired electrons in their orbitals behave as paramagnetic substances. The paramagnetism is expressed in terms of magnetic moment. The magnetic moment of an atom mu_(s)sqrt(s(s+1))(eh)/(2pimc)=sqrt((n)/(2)((n)/(2)+1))(eh)/(2pimc)" "s=(n)/(2) impliesmu_(s)=sqrt(n(n+1)) B.M. 1. B.M. (Bohr magneton)= (eh)/(4pimc) If magnetic moment is zero the substance is diamagnetic. If an ion of _(25)Mn has a magnetic moment of 3.873 B.M. Then oxidation state of Mn in ion is :

Assertion : ([Fe(CN)_6]^(3-) ion shows magnetic moment corresponding to two unpaired electrons. Reason : Because it has d^2sp^3 type hybridisation