Ce (Z = 58) and Yb (Z = 70) exhibit stable +4 and +2 oxidation states respectively. This is because

Options

A. `Ce^(4+)` and `Yb^(2+)` acquire `f^7` configurations
B. `Ce^(4+)` and `Yb^(2+)` acquire `f^0` configurations
C. `Ce^(4+)` and `Yb^(2+)` acquire `f^0` and `f^14` configurations
D. `Ce^(4+)` and `Yb^(2+)` acquire `f^7` and `f^14` configurations