A hydrocarbon `C_5H_12` gives only one chlorination product. Identify the compound.

A hydrocarbon C_5 H_(10) does not react with chlorine in dark but gives a single monochloro compound C_5 H_9 CI in bright sunlight. Identify the hydrocarbon.

Why nitration of phenol gives only ortho and para products ?

A hydrocarbon of molecular mass 72 g mo^-1 gives a single monochloro derivative and two dichloro derivatives on Photo chlorination. Give the structure of the hydrocarbon.

Hydrocarbon C_5 H_(10) does not react with chlorine but gives a single monochloro compound, C_5 H_9 Cl in bright sunlight: Identify the hydrocarbon.

When a brown compound of manganese (A) is treated with HCl it gives a gas (B). The gas taken in excess, reacts with NH_3 , to give an explosive compound (C). Identify compounds A, B and C.

A hydrocarbon ‘A’ (C_4H_8) is added with HBr in accordance with Markovnikov’s rule to give compound ‘B’ which on hydrolysis with aqueous alkali forms tertiary alcohol ‘C’ (C_4H_10O) . Identify A, B and C.

Elements of group-15 form compounds in +5 oxidation state. However, bismuth forms only one well characterised compound in +5 oxidation state. The compound is :

Which one of the following gives only one monochlore derivative ?

Compound ‘A’ with molecular formula C_4H_9Br is treated with aq. KOH solution. The rate of this reaction depends upon the concentration of the compound ‘A’ only. When another optically active isomer ‘B' of this compound was treated with aq. KOH solution, the rate of reaction was found to be dependent on concentration of compound and KOH both. Out of these two compounds, which one will be converted to the product with inverted configuration.