A hydrocarbon of molecular mass 72 g `mo^-1` gives a single monochloro derivative and two dichloro derivatives on Photo chlorination. Give the structure of the hydrocarbon.

An organic compound C_8H_18 on monochlorination gives a single monochloride. Write the structure of the hydrocarbon.

A hydrocarbon C_5H_12 gives only one chlorination product. Identify the compound.

A hydrocarbon C_5 H_(10) does not react with chlorine in dark but gives a single monochloro compound C_5 H_9 CI in bright sunlight. Identify the hydrocarbon.

What are derived fats? Give two examples.

Hydrocarbon C_5 H_(10) does not react with chlorine but gives a single monochloro compound, C_5 H_9 Cl in bright sunlight: Identify the hydrocarbon.

A solution containing 2.675 g of CoCl_3 .6NH_3 (molar mass = 267.5 g mol^-1 ) is passed through a cation exchanger. The chloride ions obtained in solution were treated with excess of AgNO_3 to give 4.78 g of AgCl (molar mass = 143.5 g mol^-1 ). The formula of the complex is : (At. mass of Ag = 108 u)

A chloro derivative (A) on treatment with zinc copper couple gives a hydrocarbon (B) with five carbon atoms. When A is dissolved in ether and treated with sodium 2, 2, 5, 5- tetramethylhexane is formed. What is the formula of the compound A ?

A dihalogen derivative (A) of a hydrocarbon having two carbon atoms reacts with alcoholic potash and forms another hydrocarbon which gives a red precipitate with ammoniacal solution of cuprous chloride. Compound ‘A' gives an aldehyde when treated with aqueous KOH. Write down the name and formula of the compound.