(R)-2-Bromooctane reacts with hydrogen sulphide `(HS^-)` ion and gives (S)-2-octanethiol with inversion of configuration at the stereocentre. Can we plan to get (R)-2-octanethiol from (R)-2-bromooctane?

S_N2 reaction occurs with inversion of configuration/ racemisation.

Calculate the number of electron, proton and neutron in sulphide ion (S*-2)

Propose mechanism of the reaction taking place when (-)-2-Bromooctane reacts with sodium hydroxide to form (+)-octane-2-ol. :

The variation of radial probability density R^2 (r) as a function of distance r of the electron from the nucleus for 3p orbital:

Alkene R-CH=CH_(2) reacts with B_(2)H_(6) in the (A) Benzene presence of H_(2)O_(2) , to give

In a right angles triangle, prove that r+2R=s.

The electric powr consumed by a device may be calculate by using either of the two expression P=I^2R or P=V^2/R . The first expression indicates that it is directly proprotinal to R whereas the second expression indicates inverse proportiionality. How can the seemingly difference dependece of P on R in these expression be explained?

For any real numbers theta and phi , we defined theta R phi if and only if sec^2 theta - tan^2 phi =1 . Then relation R is

An aqueous solution of metal ion M_1 reacts separately with reagents Q and R in excess to give tetrahedral and square planar complexes, respectively. An aqueous solution of another metal ion M_2 always forms tetrahedral complexes with these reagents. Aqueous solution of M_2 on reaction with reagent S gives white precipitate which dissolves in excess of S. The reactions are summarized in the scheme given below : M1, Q and R , respectively are :

The inverse of the function of f:R to R given by f(x)=log_(a) (x+sqrt(x^(2)+1)(a gt 0, a ne 1) is