A compound ‘X’ `(C_2H_4O)` on oxidation gives 'Y' `(C_2H_4O_2)`. 'X' undergoes haloform reaction. On treatment with HCN 'X' forms a product 'Z' which on hydrolysis gives 2-hydroxy propanoic acid. Write down structures of ‘X’ and ‘Y’.

Give the structure of H_2O_2 .

Write the reaction of XeF_4 with H_2O .

The reaction of acidified KMnO_4 with H_2O_2 gives .

Give one reaction to show that H_2O_2 is an acid.

An organic compound ‘A’ having molecular formula C_4H_8 on treatment with dil. H_2SO_4 gives B. B on treatment with conc. HCl and anhydrous ZnCl_2 gives secondary halide C. Write all the reactions and identify A, B and C.

An organic compound A (C_3H_5N) on boiling with alkali gives ammonia and sodium salt of an acid B (C_3H_6O_2) . ja reduction gives C (C_3H_9N) which with nitrous acid gives D (C_3H_8O) . Give the structural formulae of A, B, C and D.

A given nitrogen-containing aromatic compound ‘A’ reacts with Sn/HCl, followed by HNO_2 to give an unstable compound '‘B'. 'B', on treatment with phenol, forms a beautiful coloured compound 'C' with the molecular formula C_12H_10N_2O . The structure of compound 'A' is

Give one reaction to show that H_2O_2 is oxidising agent.

The compound X on treatment with acidified K_2Cr_2O_7 gives compound Y which reacts with I_2 and Na_2CO_3 to form tri-iodomethane. The compound X is :