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If x=(0.08)^(2), y=(1)/((0.08)^(2)) and ...

If `x=(0.08)^(2), y=(1)/((0.08)^(2)) and z=(1-0.08)^(2)-1` then which of the following relation is true?

A

`y lt z lt x`

B

`z lt x lt y`

C

`y lt x and x=z`

D

`x lt y and x=z`

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The correct Answer is:
To solve the problem, we need to calculate the values of \( x \), \( y \), and \( z \) based on the given definitions and then compare them to find the correct relation. ### Step-by-Step Solution: 1. **Calculate \( x \)**: \[ x = (0.08)^2 \] \[ x = 0.08 \times 0.08 = 0.0064 \] 2. **Calculate \( y \)**: \[ y = \frac{1}{(0.08)^2} \] \[ y = \frac{1}{0.0064} \] To calculate \( y \): \[ y = 156.25 \] 3. **Calculate \( z \)**: \[ z = (1 - 0.08)^2 - 1 \] First, calculate \( (1 - 0.08) \): \[ 1 - 0.08 = 0.92 \] Now square it: \[ z = (0.92)^2 - 1 \] \[ z = 0.8464 - 1 = -0.1536 \] 4. **Compare the values of \( x \), \( y \), and \( z \)**: - \( x = 0.0064 \) - \( y = 156.25 \) - \( z = -0.1536 \) Now we can arrange them: \[ z < x < y \] ### Conclusion: The correct relation is: \[ z < x < y \]
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LUCENT PUBLICATION-ALGEBRAIC IDENTITIES -Exercise - 1B
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