Two chords of a circle, of lengths 2a and 2b are mutually perpendicular. If the distance of the point, at which the chords interect, from the centre of the circle is c (c `lt` radius of the circle), then the radius of the circle is :

Options

A. `( sqrt(a^(2) + b^(2) + c^(2) ))/( 2)`
B. `sqrt( (a^2 + b^2 + c^2)/( 2) )`
C. `( sqrt( a^(2) + b^(2) - c^(2) ) )/( 2)`
D. `sqrt( (a^(2) + b^(2) - c^(2) )/(2) )`

Answer

B