A solution of sucrose (molar mass= `342gmol^-1`) is prepared by dissolving 68.4 g of it per litre of solution. What is the osmotic pressure at 300K?

A solution is prepared by dissolving 1.0 g of NaOH in water to get 250 ml of solution . Calculate its molarity .

A solution containing 15g of urea (molar mass= 60gmol^-1 ) per litre of solution in water has the same osmotic pressure (isotonic) as a solution of glucose (molar mass= 180gmol^-1 ) in water. Calculate the mass of glucose presenty in one litre of its solution.

If 1 .71 g of sugar (molar mass = 342) are dissolved in 500 cm^(3) of solution at 300 K, what will be its osmotic pressure ?

A solution is prepared by dissolving 18.25g of NaOH in distilled water to give 200ml of solution. calculate the molarity of solution.

18g of glucose (molar mass 180gmol^-1) is present in 500cm^3 of its aqueous solution. What is the molarity of the solution? What additional data is required if the molality of the solution is also required to be calculated?

A solution of glucose has been prepared at 298K dissolving 7.2 g of glucose in 100 g of water. k_f water is 1.86Km^-1 and vapour pressure of water at 298K is 0.024 atm. The vapour pressure of the solution at 298K will be

Calculate the mass of a non-volatile solute ( molar mass 40g mol^-1 ) which should be dissolved in 114g octane to reduce its vapour pressure to 80%.

How many grams of sucrose (molecular mass 342) should be dissolved in 100 g water in order to produce a soluton having difference between the boiling point and freezing point equal to 105^@C ? (K_b=0.512 Km^-1, K_f=1.86Km^-1) .

A 0.1539 molal aqueous solution of cane sugar ( molar mass-342gmol^-1 ) has a freezing of 271K while the freezing point of pure water is 273.15K. What will be the freezing point of an aqueous solution containing 5 g of glucose (mol.mass=180gmol^-1) per 100 g of solution.