Home
Class 12
MATHS
If the system of equations x – ky – z = ...

If the system of equations `x – ky – z = 0, kx – y – z=0, x + y – z = 0` has a non -zero solution then the possible values of k are

A

0,1

B

`1-1`

C

`-1,2`

D

`2,-2`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • MATRICES

    BITSAT GUIDE|Exercise BITSAT Archives |8 Videos
  • LINEAR PROGRAMMING

    BITSAT GUIDE|Exercise BITSAT ARCHIVES|3 Videos
  • PERMUTATIONS AND COMBINATIONS

    BITSAT GUIDE|Exercise BITSAT Archives|13 Videos

Similar Questions

Explore conceptually related problems

The system of equations ax + y + z = 0 , -x + ay + z = 0 and - x - y + az = 0 has a non-zero solution if the real value of 'a' is

If the system of equations x-ky-z=0,kx-y-z=0,x+y-z=0 has a nonzero solution,then the possible value of k are -1,2 b.1,2 c.0,1 d.-1,1

If the system of equations x-ky-z=0 , kx-y-z=0 , x+y-z=0 has a non-zero solution , then possible values of k are :

If the system of linear equations x + y + 3z = 0 x + 3y + k^2 z = 0 3x + y + 3z = 0 has a non -zero solution (x, y, -z) for some k in R then x + (y/z) is equal to :

The value of ‘k’ for which the set of equations 3x + ky – 2z = 0, x + ky + 3z = 0, 2x + 3y – 4z = 0 has a non – trivial solution over the set of rational is

if the system of equations x+y+z=0 , x+3y+k^2z=0 and x+2y+z=0 have a non zero solution then value of y+(x/z) is

The system of equation kx + y + z = 1, x + ky + z = k and x + y + kz = k^(2) has no solution if k equals :