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Let A={:(cosa,-sina,0),(sina,cosa,0),(0,...

Let `A={:(cosa,-sina,0),(sina,cosa,0),(0,0,1):}` then

A

`A_(a+beta)=A_(a)A_(beta)`

B

`A_(a)^(-1)=A_(a)`

C

`A_(a)^(-1)=-A_(a)`

D

`A_(a)^(2)=-l`

Text Solution

Verified by Experts

The correct Answer is:
A
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