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If the tangent at the point P `(2,4)` to the parabola `y^2 = 8x` meets the parabola `y^2 = 8x+5` at Q and R then the mid-point of QR is

A

`sqrt(3y)=3x+1`

B

`sqrt(3y)=-(x+3)`

C

`sqrt(3y)=x+3`

D

`sqrt(3y)=-(3x+1)`

Text Solution

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The correct Answer is:
a
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BITSAT GUIDE-CONIC SECTIONS-BITSAT ARCHIVES
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