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2x+sqrt(6)y=2 touches the hyperbola x^(2...

`2x+sqrt(6)y=2` touches the hyperbola `x^(2)-2y^(2)=4`, then the point of contact is

A

`(-2sqrt(6))`

B

`(-5,2sqrt(6))`

C

`(1/2,(1)/sqrt(6))`2

D

`(4,-sqrt(6)`

Text Solution

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The correct Answer is:
d
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