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If three distinct number are chosen randomly from the first 100 natural numbers, then the probability that all three of them are divisible by both 2 and 3 is `4//25` b. `4//35` c. `4//33` d. `4//1155`

A

`(4)/(55)`

B

`(4)/(35)`

C

`(4)/(33)`

D

`(4)/(1155)`

Text Solution

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The correct Answer is:
D
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