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The image of the point (1,6,3) in the li...

The image of the point (1,6,3) in the line `(x)/(1)=(y-1)/(2)=(z-2)/(3)` is (a,b,c) then a+b+c=

A

`(-1,0,7)`

B

`(-1,0,-7)`

C

`(1,0,7)`

D

`(2,0,7)`

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The correct Answer is:
c
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Find the image of the point (1,6,3) in the line (x)/(1)=(y-1)/(2)=(z-2)/(3)

Find the image of the two point (1,6,3) in the line (x)/(1)=(y-1)/(2)=(z-3)/(3)

Find the image of the point (5,9,3) in the line (x-1)/(2)=(y-2)/(3)=(z-3)/(4)

Statement-1: The point A(1,0,7) is the mirror image of the point B(1,6,3) in the line : (x)/(1)=(y-1)/(2)=(z-2)/(3) statement-2: The line :(x)/(1)=(y-1)/(2)=(z-2)/(3) bisects the line segment joining A(1,0,7) and B(1,6,3).

Statement-I The point A(1, 0, 7) is the mirror image of the point B(1,6, 3) in the line (x)/(1)=(y-1)/(2)=(z-2)/(3) . Statement-II The line (x)/(1)=(y-1)/(2)=(z-2)/(3) bisect the line segment joining A(1, 0, 7) and B(1, 6, 3) .

Find the image of the point (1, 2, 3) in the line (x-6)/(3)=(y-7)/(2)=(z-7)/(-2) .

Find the image of the point (0,2,3) in the line (x+3)/(5)= (y-1)/(2) = (z+4)/(3) .

Find image (reflection )of the point (7,4,-3) in the line (x)/(1)=(y-1)/(2)=(z-2)/(3)

If (a,b,c) is the image of the point (1,2,-3) in the line (x+1)/2=(y-3)/(-2)=z/(-1) then Find a+b+c .

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