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If a, b, c are non-coplaner vectors such...

If a, b, c are non-coplaner vectors such that `bxx c = a, c xx a = b, a xx b = c`, then which of the following is not TRUE?

A

|a|-|b|=0

B

|a| =|b| =|c| =2

C

[a b c ] =1

D

|a||b||c|=1

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the given vector equations and determine which statement is not true based on the relationships between the vectors \( a \), \( b \), and \( c \). ### Step 1: Analyze the Given Vector Equations We are given three vector equations: 1. \( b \times c = a \) 2. \( c \times a = b \) 3. \( a \times b = c \) ### Step 2: Understand the Implications of Cross Products From the properties of cross products, we know that: - The cross product of two vectors results in a vector that is perpendicular to both of the original vectors. - The magnitude of the cross product \( |u \times v| = |u||v| \sin(\theta) \), where \( \theta \) is the angle between the two vectors. ### Step 3: Calculate the Magnitudes Taking the magnitudes of the equations: 1. From \( b \times c = a \): \[ |a| = |b| |c| \sin(\theta_{bc}) \] 2. From \( c \times a = b \): \[ |b| = |c| |a| \sin(\theta_{ca}) \] 3. From \( a \times b = c \): \[ |c| = |a| |b| \sin(\theta_{ab}) \] ### Step 4: Set Up the Relationships Since \( a \), \( b \), and \( c \) are non-coplanar vectors, we can assume they have the same magnitude. Let's denote: \[ |a| = |b| = |c| = k \] Then we can rewrite the equations as: 1. \( k = k^2 \sin(\theta_{bc}) \) 2. \( k = k^2 \sin(\theta_{ca}) \) 3. \( k = k^2 \sin(\theta_{ab}) \) ### Step 5: Analyze the Angles Since the vectors are non-coplanar, the angles between them are not equal to 0 or 180 degrees. Thus, \( \sin(\theta) \) will not be zero. ### Step 6: Determine the Values of \( k \) From the equations, we can derive: \[ 1 = k \sin(\theta_{bc}), \quad 1 = k \sin(\theta_{ca}), \quad 1 = k \sin(\theta_{ab}) \] This implies: \[ k = \frac{1}{\sin(\theta_{bc})}, \quad k = \frac{1}{\sin(\theta_{ca})}, \quad k = \frac{1}{\sin(\theta_{ab})} \] ### Step 7: Conclusion on the Magnitudes Since all three magnitudes are equal, we conclude: \[ |a| = |b| = |c| = 1 \] ### Step 8: Identify the False Statement Now, we need to check the options provided in the original question to find which statement is not true based on our calculations. ### Final Answer After evaluating the relationships and the magnitudes, we find that the statement which is not true among the options provided is option number 2.
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