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Let f(x) = x[x] , x cancelin Z [.] deno...

Let f(x) = `x[x] , x cancelin Z ` [.] denotes greatest integer function), then f (x ) is equal to

A

2x

B

[x]

C

2 [x]

D

none of these

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The correct Answer is:
To solve the problem, we need to analyze the function \( f(x) = x \cdot [x] \), where \([x]\) denotes the greatest integer function (also known as the floor function). This function is defined for \( x \) not being an integer. ### Step-by-Step Solution: 1. **Understanding the Greatest Integer Function**: The greatest integer function \([x]\) gives the largest integer less than or equal to \( x \). For example: - If \( x = 0.1 \), then \([0.1] = 0\) - If \( x = 1.3 \), then \([1.3] = 1\) - If \( x = 2.7 \), then \([2.7] = 2\) 2. **Evaluating \( f(x) \) for Different Intervals**: We will evaluate \( f(x) \) for different ranges of \( x \): - **For \( 0 < x < 1 \)**: \[ f(x) = x \cdot [x] = x \cdot 0 = 0 \] - **For \( 1 < x < 2 \)**: \[ f(x) = x \cdot [x] = x \cdot 1 = x \] - **For \( 2 < x < 3 \)**: \[ f(x) = x \cdot [x] = x \cdot 2 = 2x \] 3. **Summarizing the Function**: From the evaluations, we can summarize \( f(x) \) as follows: - \( f(x) = 0 \) for \( 0 < x < 1 \) - \( f(x) = x \) for \( 1 < x < 2 \) - \( f(x) = 2x \) for \( 2 < x < 3 \) 4. **Graphing the Function**: - For \( 0 < x < 1 \), the graph is a horizontal line at \( y = 0 \). - For \( 1 < x < 2 \), the graph is a line with a slope of 1 (i.e., \( y = x \)). - For \( 2 < x < 3 \), the graph is a line with a slope of 2 (i.e., \( y = 2x \)). 5. **Conclusion**: The function \( f(x) \) is piecewise defined and varies based on the interval in which \( x \) lies. The function does not have a single expression that describes it for all \( x \), but it can be represented as: \[ f(x) = \begin{cases} 0 & \text{for } 0 < x < 1 \\ x & \text{for } 1 < x < 2 \\ 2x & \text{for } 2 < x < 3 \end{cases} \]
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