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If temperature of black body increases f...

If temperature of black body increases from `300K` to `900K`, then the rate of energy radiation increases by

A

81

B

3

C

9

D

2

Text Solution

Verified by Experts

The correct Answer is:
a
Acoording to Stefan.s law `rho=(E )/(t)=sigmaAeT^(4)`
So , we can write as
`(E_(2))/(E_(1))=(T_(2)/T_(1))^(4)`
`(E_(2))/(E_(1))=((900)/(300))^(4)rArr(E_(2))/(E_(1))=(3)^(4)`
`E_(2)=81E_(1)rArr(E_(2))/(E_(1))=81`
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    A
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    B
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