An iceberg of density `900kg//m^(3)` is floating in water of density `1000 kg//m^(3)`. The percentage of volume of ice cube outside the water is

Options

A. `20%`
B. `35%`
C. `10%`
D. `11%`

Answer

c

Explanation

Let the volume of ice-berg isV and its density is `rho` .If this ice =berg floats in water with volume `V_(in)` inside it , then
`V_("in")sigmag=Vrhog`
`sig=` density of water
`rArrV_(in)=((rho)/(sigma))*V`
`rArrV_("out")=V-V_("in")`
`[(sigma-rho)/(sigma)]V=(1000-900)/(1000)V`
`=(V)/(10)`
`rArrV_("out")//V=0.1=10%`