In Fig, `E =5` volt , `r = 1 Omega, R_(2) = 4 Omega, R_(1) = R_(3) = 1 Omega` and `C = 3 muF`. Then the numbercal value of the charge on each plate of the capacitor is

Options

A. `24 muC`
B. `12muC`
C. `6muC`
D. `3muC`

Answer

c

Explanation

Current will flow only through the branch containing resistance `R_(2)`
`thereforei=(E )/(R_(2)+r)=(5)/(4+1)=1A`
Potential difference across `R_(2)`
If q be the charge on each plate of capacitor , then `(q)/(c )+(q)/(c )=4`
or `(2q)/(c )=4`
or `(2q)/(3xx10^(-6))=4`
`q=6muC`