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Work done in increasing the size of a so...

Work done in increasing the size of a soap bubble from a radius of 3cm to 5cm is nearly (Surface tension of soap solution `=0.03Nm^-1`)

A

`0.2pimJ`

B

`2pimJ`

C

`0.4 mJ`

D

`4pimJ`

Text Solution

Verified by Experts

The correct Answer is:
d
Work done = Change in surface energy `r_(2)=5cm`
`r_(1)=3cm`
`rArrW=2Txx4pi(r_(2)^(2)-r_(1)^(2))`
`=2xx0.03xx4pi[(5)^(2)-(3)^(2)]xx10^(-4)`
`=0.4pimJ`
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