In the given circuit,

The current through battery is

Options

A. 0.5A
B. 1A
C. 1.5A
D. 2.5A

Answer

C

Explanation

In the given circuit, diode `D_(1)` is reverse biased, so it will not conduct but `D_(2), D_(3)` are forward biased, so they will conduct, hence corresponding equivalent circuit. For the given circuit is

Now the equivalent resistance of the circuit is `R_(eq)= ((5+5) xx 20)/((5+5)+20) + (20)/(3) Omega`
Current through battery, `l= (10V)/((20)/(3)Omega)=1.5A`