In the given circuit, it is observed that the current I is independent of the value of the resistance `R_6`. Then the resistance values must satisfy
.

Options

A. `(1)/(R_(5)) + (1)/(R_(6))= (1)/(R_(1) + R_(2)).(1)/(R_(3) + R_(4))`
B. `R_(1)R_(4)= R_(2)R_(3)`
C. `R_(1)R_(2)R_(5)= R_(3)R_(4)R_(6)`
D. `R_(1)R_(3)=R_(2)R_(4)=R_(5)R_(6)`

Answer

B

Explanation

From the given circuit, we can say that l is independent of resistance `R_(5)`, so no current flows through `R_(5)`. This required that the junction of `R_(1) and R_(2)` is at the same potential as the junction of `R_(3) and R_(4)` (`therefore` Wheatstone bridge condition)
So, `(R_(1))/(R_(2))= (R_(3))/(R_(4))`
or `R_(1)R_(4)= R_(3)R_(2)`