Which of the following is an incorrect set of quantum members?

Options

A. n=2,l=0,m=0
B. n=1,/=0,m=0
C. n=3,l=3,m=0
D. n=2,l=1,m=1

Explanation

To determine which set of quantum numbers is incorrect, we need to understand the rules governing quantum numbers. There are four quantum numbers:

1. **Principal Quantum Number (n)**: This can take positive integer values (n = 1, 2, 3,...).
2. **Azimuthal Quantum Number (l)**: This can take values from 0 to (n-1). For example, if n = 2, l can be 0 or 1.
3. **Magnetic Quantum Number (m_l)**: This can take values from -l to +l. For example, if l = 1, m_l can be -1, 0, or +1.
4. **Spin Quantum Number (m_s)**: This can take values of +1/2 or -1/2.

Now, let's analyze the possible sets of quantum numbers to identify the incorrect one.

### Step-by-Step Solution:

1. **Identify the Sets of Quantum Numbers**: Review the given sets of quantum numbers. Each set should consist of four values: (n, l, m_l, m_s).

2. **Check Each Set Against the Rules**:
- For each set, check if the values of l, m_l, and m_s comply with the rules based on the value of n.
- Ensure that l is in the range of 0 to (n-1).
- Ensure that m_l is in the range of -l to +l.
- Ensure that m_s is either +1/2 or -1/2.

3. **Example Analysis**:
- **Set 1**: (n=2, l=1, m_l=0, m_s=+1/2)
- n = 2 → l can be 0 or 1 (valid)
- l = 1 → m_l can be -1, 0, +1 (valid)
- m_s = +1/2 (valid)
- **Set 2**: (n=3, l=2, m_l=1, m_s=-1/2)
- n = 3 → l can be 0, 1, or 2 (valid)
- l = 2 → m_l can be -2, -1, 0, +1, +2 (valid)
- m_s = -1/2 (valid)
- **Set 3**: (n=3, l=3, m_l=0, m_s=+1/2)
- n = 3 → l can be 0, 1, or 2 (invalid since l cannot equal n)
- **Set 4**: (n=2, l=1, m_l=1, m_s=-1/2)
- n = 2 → l can be 0 or 1 (valid)
- l = 1 → m_l can be -1, 0, +1 (valid)
- m_s = -1/2 (valid)

4. **Conclusion**: The incorrect set of quantum numbers is **Set 3**: (n=3, l=3, m_l=0, m_s=+1/2) because l cannot equal n.

### Final Answer:
The incorrect set of quantum numbers is **(n=3, l=3, m_l=0, m_s=+1/2)**.