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A graph is ploted between log K virsus (...

A graph is ploted between log K virsus `(1)/(T)` for calculation of activation energy `(E_(a))`. The correct plot is

A

B

C

D

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The correct Answer is:
b
According to Arrhenius equation .s
log K=logA`-(E_(a))/(2.303R)(1)/(T)`
on comparing it with the equation of st . Line y= mx + c plot (b) is the correct answer.
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