If` ((0.51xx10^(-10))/4)` m is the radius of smallest electron orbit in hydrogen like atom, then this atom is.

Options

A. hydrogen atom
B. `He^(+)`
C. `Li^(2+)`
D. `Be^(3+)`

Answer

D

Explanation

Radius of hydrogen like atom, `r_(n)= (n^(2))/(Z) r_(0)` where, `r_(0)= 0.51 xx 10^(-10)m` and `r_(n)= (0.51 xx 10^(-10)m)/(4)`
At ground state, n=1 Hence, the atom is `Be^(3+) [because Z=4]`