A mixture of bromo trichloride and hydrogen is subjected to silent electric discharge to form x and HCl. X is mixed with `NH_(3)` and heated to `200^(@)C` to form y. Then formula of y is

Options

A. `B_(2)O_(3)`
B. `B_(3)N_(3)H_(6)`
C. `H_(3)BO_(3)`
D. `B_(2)H_(6)`

Explanation

To solve the question step by step, we will break down the reactions involved and identify the compounds formed.

### Step 1: Identify the initial reaction
The question states that a mixture of bromotrichloride (BCl3) and hydrogen (H2) is subjected to silent electric discharge. The reaction can be represented as follows:

\[ \text{BCl}_3 + \text{H}_2 \xrightarrow{\text{Electric Discharge}} \text{X} + \text{HCl} \]

### Step 2: Determine the product X
From the reaction, we know that the product X formed is diborane (B2H6). The balanced reaction can be represented as:

\[ 2 \text{BCl}_3 + 6 \text{H}_2 \rightarrow \text{B}_2\text{H}_6 + 6 \text{HCl} \]

### Step 3: Mix X with ammonia
Next, we mix the product X (B2H6) with ammonia (NH3) and heat it to 200°C (473 K). The reaction can be represented as:

\[ \text{B}_2\text{H}_6 + \text{NH}_3 \xrightarrow{\text{Heat}} \text{Y} \]

### Step 4: Identify the product Y
When diborane reacts with ammonia, it forms borazine (B3N3H6), which is often referred to as inorganic benzene. The balanced reaction can be represented as:

\[ \text{B}_2\text{H}_6 + 6 \text{NH}_3 \rightarrow \text{B}_3\text{N}_3\text{H}_6 + 3 \text{H}_2 \]

### Conclusion
Thus, the formula of compound Y is:

\[ \text{Y} = \text{B}_3\text{N}_3\text{H}_6 \]

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