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Given the hypothetical reaction mechanis...

Given the hypothetical reaction mechanism
E and the rate as The rate determining step is

A

step I

B

step II

C

step III

D

step IV

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The correct Answer is:
D
Among the formation of B, C, D and E, the slowest step is the rate determining step. As formation of B, i.e. 0.002 mol/h per mole of A is the slowest step. Hence, step-(I) is the rate determining step.
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What is the rate determining step of a reaction ?

Consider the above reaction and answer A to E. Which step is rate determining step?

For a hypothetical reaction, A + B + C to Products, the rate law is determined to be rate = k[A][B]^(2) . If the concentration of B is doubled without changing the concentration of A and C, the reaction rate:

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S_(N^(1)) reaction is a first order nucleophilic substitution e.g. CH_(3)-overset(CH_(3))overset(|)underset(CH_(3))underset(|)C-Br+H_(2)Oto CH_(3)-overset(CH_(3))overset(|)underset(CH_(3))underset(|)C-OH+HBr The concentration of nucleophile does not appear in the rate law expression. Reaction rate k[RX] In a mulptistep organic reaction , the rate-limiting step is the slowest step . Rate determining step is represented by the following energy level diagram: A reaction energy level diagram for an S_(N^(1)) reaction .The rate limiting step is spontaneous dissociation of an alkyl halide to give a carbocation intermediate: In the graph 3 for S_(N^(1)) reaction the rate limiting step is the spontaneous dissociation of alkyl halide and is given by

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