In a compound `C, H, N` atoms are present in `9:1:3.5` by weight. Molecular weight of compound is `108`. Its molecular formula is:

Options

A. `C_(2) H_(6) N_(2)`
B. `C_(3) H_(4) N`
C. `C_(6) H_(8) N_(2)`
D. `C_(9) H_(12) N_(3)`

Answer

C

Explanation

`:. " "` Empirical formula = `C_(3) H_(4) N`
The empirical formula mass= `3xx 12 +4 xx 1 + 14 = 54 ` g
Given molecular mass =108 g
Thus ` n =(108)/(54)` =2
Hence, molecular formula = (Empirical formula) `xx 2`
`(C_(3) H_(4) N) xx 2 = C_(6) H_(8) N_(2)`