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4(1)/(2)-(5)/(8)+12(1)/(4)-3(1)/(8)=?...

`4(1)/(2)-(5)/(8)+12(1)/(4)-3(1)/(8)=?`

A

`12 (1)/(4)`

B

13

C

`12 (3)/(4)`

D

12

Text Solution

AI Generated Solution

The correct Answer is:
To solve the expression \( 4\frac{1}{2} - \frac{5}{8} + 12\frac{1}{4} - 3\frac{1}{8} \), we will follow these steps: ### Step 1: Convert mixed numbers to improper fractions 1. Convert \( 4\frac{1}{2} \) to an improper fraction: \[ 4\frac{1}{2} = 4 \times 2 + 1 = 8 + 1 = \frac{9}{2} \] 2. Convert \( 12\frac{1}{4} \) to an improper fraction: \[ 12\frac{1}{4} = 12 \times 4 + 1 = 48 + 1 = \frac{49}{4} \] ### Step 2: Rewrite the expression Now, we can rewrite the expression using the improper fractions: \[ \frac{9}{2} - \frac{5}{8} + \frac{49}{4} - \frac{3}{8} \] ### Step 3: Find a common denominator The denominators are 2, 8, and 4. The least common multiple (LCM) of these denominators is 8. We will convert each fraction to have a denominator of 8: 1. Convert \( \frac{9}{2} \): \[ \frac{9}{2} = \frac{9 \times 4}{2 \times 4} = \frac{36}{8} \] 2. \( \frac{5}{8} \) remains \( \frac{5}{8} \). 3. Convert \( \frac{49}{4} \): \[ \frac{49}{4} = \frac{49 \times 2}{4 \times 2} = \frac{98}{8} \] 4. \( \frac{3}{8} \) remains \( \frac{3}{8} \). ### Step 4: Rewrite the expression with a common denominator Now the expression becomes: \[ \frac{36}{8} - \frac{5}{8} + \frac{98}{8} - \frac{3}{8} \] ### Step 5: Combine the fractions Combine all the fractions: \[ \frac{36 - 5 + 98 - 3}{8} = \frac{36 + 98 - 5 - 3}{8} = \frac{126}{8} \] ### Step 6: Simplify the fraction Now simplify \( \frac{126}{8} \): \[ \frac{126 \div 2}{8 \div 2} = \frac{63}{4} \] ### Step 7: Convert to mixed number (if necessary) To convert \( \frac{63}{4} \) to a mixed number: \[ 63 \div 4 = 15 \quad \text{(remainder 3)} \] Thus, \( \frac{63}{4} = 15\frac{3}{4} \). ### Final Answer The final answer is: \[ 15\frac{3}{4} \]
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