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The simplified of ((1)/(3)-:(1)/(3) xx(...

The simplified of `((1)/(3)-:(1)/(3) xx(1)/(3))/((1)/(3)-:(1)/(3)"of"(1)/3)-(1)/(9)` is

A

0

B

`(1)/(9)`

C

`(1)/(3)`

D

1

Text Solution

AI Generated Solution

The correct Answer is:
To simplify the expression \(\frac{\frac{1}{3} \div \frac{1}{3} \times \frac{1}{3}}{\frac{1}{3} \div \frac{1}{3} \text{ of } \frac{1}{3} - \frac{1}{9}}\), we will follow these steps: ### Step 1: Simplify the numerator The numerator is \(\frac{1}{3} \div \frac{1}{3} \times \frac{1}{3}\). - First, calculate \(\frac{1}{3} \div \frac{1}{3}\): \[ \frac{1}{3} \div \frac{1}{3} = 1 \] - Now, multiply by \(\frac{1}{3}\): \[ 1 \times \frac{1}{3} = \frac{1}{3} \] ### Step 2: Simplify the denominator The denominator is \(\frac{1}{3} \div \frac{1}{3} \text{ of } \frac{1}{3} - \frac{1}{9}\). - First, calculate \(\frac{1}{3} \div \frac{1}{3}\): \[ \frac{1}{3} \div \frac{1}{3} = 1 \] - Now, calculate \(1 \text{ of } \frac{1}{3}\): \[ 1 \text{ of } \frac{1}{3} = \frac{1}{3} \] - Now, subtract \(\frac{1}{9}\): \[ \frac{1}{3} - \frac{1}{9} \] To subtract these fractions, we need a common denominator. The least common multiple of 3 and 9 is 9. - Convert \(\frac{1}{3}\) to have a denominator of 9: \[ \frac{1}{3} = \frac{3}{9} \] - Now, perform the subtraction: \[ \frac{3}{9} - \frac{1}{9} = \frac{2}{9} \] ### Step 3: Combine the results Now we can substitute the simplified numerator and denominator back into the expression: \[ \frac{\frac{1}{3}}{\frac{2}{9}} \] ### Step 4: Simplify the fraction To divide by a fraction, we multiply by its reciprocal: \[ \frac{1}{3} \div \frac{2}{9} = \frac{1}{3} \times \frac{9}{2} = \frac{9}{6} \] ### Step 5: Simplify \(\frac{9}{6}\) Now simplify \(\frac{9}{6}\): \[ \frac{9}{6} = \frac{3}{2} \] ### Step 6: Final Calculation Now we have: \[ \frac{3}{2} - \frac{1}{9} \] To subtract these fractions, we need a common denominator. The least common multiple of 2 and 9 is 18. - Convert \(\frac{3}{2}\) to have a denominator of 18: \[ \frac{3}{2} = \frac{27}{18} \] - Convert \(\frac{1}{9}\) to have a denominator of 18: \[ \frac{1}{9} = \frac{2}{18} \] - Now, perform the subtraction: \[ \frac{27}{18} - \frac{2}{18} = \frac{25}{18} \] ### Conclusion The simplified value of the expression is \(\frac{25}{18}\).
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