Home
Class 11
MATHS
Sixteen players S(1), S(2), S(3), cdots,...

Sixteen players `S_(1), S_(2), S_(3), cdots, S_(16)` play in a tournament. Number of ways in which they can be grouped into eight pairs so that `S_(1)` and `S_(2)`, are in different groups, is equal to

A

`((14)!)/(2^(6).6!)`

B

`((15)!)/(2^(7).7!)`

C

`((14)!)/(2^(7).6!)`

D

`((14)!)/(2^(6).7!)`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

As_(2)S_(3) sol is

If S_1, S_2, S_3 are the sum of first n natural numbers, their squares and their cubes, respectively, show that 9 S_2^(2)= S_3(1+8 S_1)

The hydrogen-like species Ļi^(2+) is in a spherically symmetric state S_(1) with one radial node. Upon absorbing light the ion undergoes transition to a state S_(2) The state S_(2) has one radial node and its energy is equal to the ground state energy of the hydrogen atom. The state S_(1) is: 1s, 2s, 2p, 3s

If S_1.S_2.S_3 are the sum of the first n natural numbers, their squares and their cubes respectively, show that 9S_2^2=S_3(1+8S_1)