Three identical point masses, each of mass 1 kg lie in the x-y plane at points (0,0),(0,0.2 m) and (0.2 m, 0)
The net gravitational force on the mass at the origin is

Options

A. `1.67 xx 10^(-9)(overset ^i +overset ^ j)N`
B. `3.34 xx 10^(-10)(overset ^i +overset ^ j)N`
C. `1.67 xx 10^(-9)(overset ^i - overset ^ j)N`
D. `3.34 xx 10^(-10)(overset ^i + overset ^ j)N`

Answer

A

Explanation

Let particle A lies at origin, Particle B and C on y and x-axis respectively
`overset rarr (F_(AC))=("Gm"_(A)m_(B))/(r_(AB)^(2))overset^ i= (6.67 xx 10^(-11) xx 1 xx 1)/((0.2)^(2))overset ^ i =1.67 xx 10^(-9) overset ^i N,`
Similarly `overset rarr(F_(AB))=1.67 xx 10^(-9)overset ^j N`
`therefore` Net force on particle A `overset rarr F = overset rarr F _(AC) + overset rarr F_(AB)=1.67 xx 10^(-9)( overset ^ i+ overset ^j)N`