An isolated particle of mass m is moving in a horizontal plane (x-y), along the x-axis, at a certain height above the ground. It suddenly explodes into two fragments of masses m/4 and 3m/4. An instant later, the smaller fragment is at y = + 15 m. The larger fragment at this instant is at

Options

A. y = -5 m
B. y = + 20 m
C. y = + 5m
D. y = -20m

Answer

A

Explanation

Since there is no external force acting on the particle hence
`Y_(CM)=(m_(1)Y_(1)+m_(2)Y_(2))/(m_(1)+m_(2))=0`
Hence, `(m/4) times 15+((3m)/4) times Y_(2)=0" "rArr Y_(2)=-5m`