A systeme consists of three particles, each of mass m and located at (1, 1), (2, 2) and (3, 3). The co-ordinates of the centre of mass are

Options

A. (1, 1)
B. (2, 2)
C. (3, 3)
D. (6, 6)

Answer

B

Explanation

The coordinates of CM of three particles are
`x=(m_(1)x_(1)+m_(2)x_(2)+m_(3)x_(3))/(m_(1)+m_(2)+m_(3)) and y=(m_(1)y_(1)+m_(2)y_(2)+m_(3)y_(3))/(m_(1)+m_(2)+m_(3))`
here `m_(1)=m_(2)=m_(3)=m`
So `x=((x_(1)+x_(2)+x_(3))m)/(3m)=2 and y=((y_(1)+y_(2)+y_(3))m)/(3m)=2`