A uniform rod of length 1 m is bent at its midpoint to make `90^(@)` angle. Calculate the distance of the centre of mass from the centre of the rod.

Options

A. 15 cm
B. 17.7 cm
C. 18.5 cm
D. 20 cm

Answer

B

Explanation

`c_(1) and c_(2)` denote the centres of mass of OB and OA respectively.
`therefore (c_(1)c_(2))^(2)=(25)^(2)+(25)^(2), " "therefore c_(1)c_(2)=25sqrt(2)=35.35cm`
`therefore` Distance of effective centre of mass = `(35.35)/2=17.7cm`
Distance (O to C.M.) = Distance (`c_(1)` to C.M.) = (C.M. to `c_(2)`)
`therefore` Distance C.M. from centre of rod = 17.7 cm