The resultant of two forces acting at an angle of `120^(@)` is 10kg wt and is perpendicular to one of the forces. The force is

Options

A. `10 sqrt(3)` kg wt
B. `20 sqrt(3)` kg wt
C. 10 kg wt
D. `(10)/(sqrt(3))`

Answer

D

Explanation

If `vecF_(1) and vecF_(2)` are the forces and resultant `vecR` is perpendicular to `vecF_(1),R=10` kg wt. Then `"tan" 30^(@), (F_(1))/(R)`
`F_(1)=R "tan" 30^(@)=(10)/( sqrt(3))` Kgwt