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A car travelling at 36 kmh^(-1) due Nor...

A car travelling at `36 kmh^(-1)` due North turns West in 5 seconds and maintain the same speed. The acceleration of the car is

A

`3 sqrt(2)ms^(-2)`

B

`(3)/(sqrt(2))ms^(-2)`

C

`2 sqrt(3) ms^(-2)`

D

`2 sqrt(2) ms^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
D

`vecv_(a)` 36km/h=10m/s (due West)
`vecv_(A)=` 10m/s (due North)
`vecv_(A)=-10` m/s (due North)=10m/s (due South)
`Deltay= sqrt(v^(2)+v^(2))= sqrt(2)v= sqrt(2)xx10`
`alpha=(Deltav)/(t)=( sqrt(2)xx10)/(5)=2 sqrt(2)m//s^(2)`
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