The distance covered by a body in time `(5.0pm0.6)`s is `(40.0pm0.4)`m. Calculate the speed of the body. Also determine the percentage error in the speed.

Explanation

Here s=40,0 `pm`0.4m and t=5.0`pm`0.6
Therefore, speed, As V=`(s)/(t) therefore` ,Here `triangle`s-=0.4m,s=40.0m, `triangle`t =0.6s, t=15.0
Therefore,Hence, `v=(8.0 pm 104)ms^(-1)`
Percentage error,`((triangleV)/(v)xx100)=0.13xx100=13%`