An electron in hydrogen atom first jumps from `n^(th)` excited state to `(n − 1)^(th)` excited state and then from `(n-1)^(th)` , then excited state to `(n-2)^(th)` excited state. If the ratio of energy of photons emitted in these two cases is `5/27` then find the ratio of momentums.

Options

A. `0.275`
B. 4.7
C. 5.4
D. 0.185

Answer

D

Explanation

Ratio of energy of photons `= 5/(27) =E `
`E alpha 1/lamda (E=(hc)/lamda) and p prop E ( "since, p" = E/c)`
atio of momentumas = 0.185