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The orbital speed of the electron in the...

The orbital speed of the electron in the ground state of hydrogen is v. What will be its orbital speed when it is excited to the energy state-3.4 eV?

A

2v

B

`v/2`

C

`v/4`

D

`v/8`

Text Solution

Verified by Experts

The correct Answer is:
B
Energy state-3.4 eV corresponds to a level n given by `(-13.4eV )/n^2=-3.4eV` which gives n = 2. Now, orbital speed `v_0 alpha(1)/n` . Hence the orbital speed in the excited state is `upsilon/2` .
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