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The ionisation potential of hydrogen is ...

The ionisation potential of hydrogen is 13.6V. The energy required to remove an electron from the second orbit of hydrogen is

A

3.4 eV

B

6.8 eV

C

27.2 eV

D

54.4 eV

Text Solution

Verified by Experts

The correct Answer is:
A
`E_n = -(13.6)/n^2 eV`
`:. E_2 =-3.4 eV and E_(oo) = 0 :. ` Required energy `= E_(oo) - E_2 = 3.4 eV`
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