Statement I A radiation of wavelength `1216Å` is emitted when an hydrogen atom goes from its first excited state back to the ground state.
Statement II : Minimum energy required to excite an hydrogen atom from n = 1 to n = 2 state is 10.2 eV.

Options

A. Statement I is True, Statement II is True, Statement II is a correct explanation for Statement I
B. Statement I is True, Statement II is True, Statement II is not a correct explanation for Statement I
C. Statement I is True, Statement II is False.
D. Statement I is False, Statement II is True.

Answer

A

Explanation

Energy of electron in ground state is -13.6 eV.
Energy of electron in n = 2 state is -3.4eV.
Therefore, an energy of 10.2eV will excite the electron from the ground state to the 1st excited state i.e. to the next higher level n = 2.
When the electron jumps back to the ground state it emits the same amount of energy in the form of electromagnetic waves. The wavelength of the emitted radiation is
`1/lamda=v/c=E/(hc)implies (hc)/E = (6.6xx10^(-34)xx3xx10^8)/(10.2 xx1xx1.6 xx10^(-19))=1.216 xx10^(-7)m = 1216Å`
The assertion is also true and is based on the values given in the reason.