Number of moles of `K_2Cr_2O_7`, reduced by one mole of `Sn^(2+)` ions is:

Options

A. `1 //3`
B. `3`
C. `1//6`
D. `6`

Answer

A

Explanation

`Cr_2 O_(7)^(2-) + 3 sn^(2+) + 14 H^(+) to 2 Cr^(3+) + 3Sn^(3+) + 7 H_2 O`
3moles of ` Sn^(2+)` ions reduce = 1 mole of ` Cr_2 O_(7)^(2-)` = 1 mole of `K_2 Cr_2 O_(7)`
1 mole of `Sn^(2+) ` ions will be reduce ` =1//3` mole of ` K_2 Cr_2 O_(7)`