Water saturated with air (20% 0, and 80% N) at 1 atm and 298 K contains 8.9 x 10^-3 g/ L dissolved oxygen. Its solubility under 25 atm pressure of will be a)8.9 × 10 − 3 g L − 1 b)1.1125 g L − 1 c)1.5642 g L − 1 d)1.834 × 10 − 2 g L − 1

Options

A. `8.9 xx 10^(-3)g L^(-1)`
B. `1.1125 g L^(-1)`
C. `1.5642 g L^(-1)`
D. `1.834 xx 10^(-2)g L^(-1)`

Answer

B

Explanation

Since `p= k_(H)c`, we have 0.20 atm `= K_(H ) (8.9 xx 10^(-3) gL^(-1)) and 25 atm = K_(H)C`
Hence, `c= (8.9 xx 10^(-3)gL^(-1))` (25 atm)/0.20 atm = `1.1125 gL^(-1)`