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The vapour pressure of water is 92.5 mm ...

The vapour pressure of water is 92.5 mm at 300 K. The V.P. of 1 molal aqueous solution of non volatile non electrolyte solute is

A

90.84mm

B

87.32mm

C

69.50mm

D

53.21mm

Text Solution

Verified by Experts

The correct Answer is:
A
`(P_(A)^(@)- P_(s))/(P_(A)^(@))= (n_(B))/(n_(A) + n_(B))`
`therefore (92.5-P_(S))/(92.5) =(1)/(1+ (1000)/(18))`
`P_(s)= 90.84 mm`
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