The vapour pressure of pure benzene at `88^@C` is 957 mm and that of toluene at the same temperature is 379.5 mm. Calculate the composition of benzene toluene mixture boiling at `88^@C` at 1 atm pressure

Options

A. `x_("benzene")= 0.66, x_("toluene")= 0.34`
B. `x_("benzene")= 0.34, x_("toluene")= 0.66`
C. `x_("benzene")= x_("toluene")= 0.5`
D. `x_("benzene")= 0.75, x_("toluene")= 0.25`

Answer

A

Explanation

`p= p_("benzene")^(@) x_("benzene") + p_("toluene")^(@) x_("toluene")`
`760= 957. x_("benzene") + 379.5 (1- x_("benzene"))`
`x_("benzene")= 0.66 and x_("toluene")= 1-0.66=0.34`