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The molal freezing point constant of wat...

The molal freezing point constant of water is `" 1.86 Km"^(-1)`. If 342 g of cane sugar `(C_(12)H_(22)O_(11))` is dissolved in 1000 g of water, the solution will freeze at

A

`-1.86^(@)C`

B

`1.86^(@)C`

C

`-3.92^(@)C`

D

`2.42^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
A
`Delta T_(f)= k_(f)m`, if solution is 1 molal
`Delta T_(f)= k_(f) = 1.86^(@)C`
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